(1+0,05/12)^(12x)=2

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Solution for (1+0,05/12)^(12x)=2 equation: 



(1+0.05/12)^(12x)=2

We move all terms to the left:

(1+0.05/12)^(12x)-(2)=0



Domain of the equation: 12)^12x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(0.05/12+1)^12x-2=0

We multiply all the terms by the denominator


(0.05-2*12+1)^12x=0

We add all the numbers together, and all the variables

(-22.95)^12x=0

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